Krish
The answer is in a table I made http://lottoposter.com/forum_posts.asp?TID=540 - Combinations per Pool . For a Pool 34 Pick 7 your chances of getting any Seven is 1 in 5,379,616.
To calculate for any Contiguous Numerical Order or Consecutive Sevens - first work out how many there are, which is 28 -
01 02 03 04 05 06 07
02 03 04 05 06 07 08
.
.
.
28 29 30 31 32 33 34
Then, simply multiply by the ratio to get the probability
28 x 1/5379616 = 0.0000052 or 0.00052%
What this means is any set of 28 numbers you care to nominate has the same chance of having the winning number.
If you played any 28 numbers once a week for a year then your chances of a first prize are 52 x 28 x 1/5379616 = 0.0002704 or 0.02704%. For 50 years you are looking at 50 x 52 x 28 x 1/5379616 = 0.01352 or 1.352%.
If you increased the lines played to 1000 a week then over 50 years it is likely but still not certain that you would win first prize ie 50 x 52 x 1000 x 1/5379616 = 0.0096 or 96%. The number of plays you have made if all are different at 2,600,000 is about 48% of the possibilities.
Chances are that you will have spent more than what you get back as first prize no matter how much you increase the plays. In other words the luck element can't be elimiminated from being ahead in Lotto.
Regards
Colin
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*Lotto Draws have no relationship to one another; the integers serve just as identifiers. Any prediction calculation on one history of draws for a same type game is just as irrelevant as another.
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